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Rolling Thunder

{X}{R}{R}

Sorcery

BFZBattle for Zendikar#154uncommon

"Zendikar is always angry, though I've never seen that anger so precisely directed." —Nablus, North Hada trapper

Finishes
Nonfoil · Foil
Border
black
Frame
2015
Pull rate
about 1 per booster–1 in 1449
Illustrator
Yohann Schepacz
Found in
Welcome Deck 2016 Red Deck · Battle for Zendikar MTGO Redemption Foil · 5 more
Printings7EDHREC rank#13,212
CommanderLegalModernLegalStandardNot legal
Format legality

Constructed

StandardNot legal
PioneerLegal
ModernLegal
LegacyLegal
VintageLegal
PauperLegal

Commander

CommanderLegal
Pauper CommanderLegal
Duel CommanderLegal
PreDHLegal
OathbreakerLegal
Tiny LeadersLegal

Arena

AlchemyNot legal
HistoricNot legal
TimelessNot legal
BrawlNot legal
Standard BrawlNot legal
Competitive BrawlNot legal
GladiatorNot legal

Other

PremodernLegal
Old SchoolNot legal
Penny DreadfulNot legal
Future StandardNot legal
Rolling Thunder deals X damage divided as you choose among any number of targets.
Plays as:
Mana SinkDamage WinX Spell
Market · per finishspark updated 2h ago · prices as of 2026-08-30
Nonfoil0.0%
$0.14
$0.02 low$0.01 gapTCGplayer
Foil0.0%
$1.07
$0.44 low$0.24 gapTCGplayer
Cheapest playable copy$0.14· across 7 printings· you're viewing it

Rulings

4 · latest Aug 25, 2015
  • WotCAug 25, 2015

    If Rolling Thunder is copied, the copy will retain the original damage divsion. The spell or ability will likely allow you to choose new targets, but you can’t change the way damage is divided.

  • WotCAug 25, 2015

    If some, but not all, of the targets become illegal by the time Rolling Thunder tries to resolve, the original division of damage still applies, but no damage is dealt to illegal targets. If all the targets are illegal, the spell won’t resolve.

  • WotCAug 25, 2015

    You choose how many targets Rolling Thunder has and how the damage is divided as you cast the spell. Each target must receive at least 1 damage.

  • WotCOct 4, 2004

    If X is 0, you can’t choose any targets.